6x^2-(10+3x^2-2x=)

Solution for 6x^2-(10+3x^2-2x=) equation:

6x^2-(10+3x^2-2x=)

We move all terms to the left:

6x^2-(10+3x^2-2x-())=0


We calculate terms in parentheses: -(10+3x^2-2x-()), so:

10+3x^2-2x-()

determiningTheFunctionDomain
3x^2-2x+10-()

We add all the numbers together, and all the variables

3x^2-2x

Back to the equation:

-(3x^2-2x)


We get rid of parentheses

6x^2-3x^2+2x=0

We add all the numbers together, and all the variables

3x^2+2x=0

a = 3; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·3·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*3}=\frac{-4}{6}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*3}=\frac{0}{6}
=0
$